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Automata Theory 
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Description
I don't know either, but I'm responsible for knowing it.
Comments
TrackStar
707 Photos

Yea, the problem is with the first one... it does it over and over and never lets you get to the rest of the problem... your teach as PUNK'd you!

6/13/2006 3:22:35 AM

Linus
24 Photos

All I see is "wtf?"

6/13/2006 3:24:58 AM

shchmue
21 Photos

i see... umm... set theory symbols... and electrical engineering symbols? i'd look it up but then it would lose the intended mystique.

6/13/2006 3:31:26 AM

Imperfect Clark
116 Photos

^^^

NO

6/13/2006 3:57:02 AM

CallMeEleanor
131 Photos

Child's play.



I, as always, admire your academic endeavors in awe and respect.

6/13/2006 4:05:42 AM

CallMeEleanor
131 Photos

x2.

[Edited by CallMeEleanor on 6/12/2006 11:05:52 PM. Reason for edit: /]

6/13/2006 4:05:43 AM

ForTheOrca
6 Photos

NFA? I never got headaches during tests until I took that class. NFA M is a 5-tuple that...gggggzzzzzurgegle...



6/13/2006 4:10:02 AM

Imperfect Clark
116 Photos

Yeah, it's the potential accepting states are selected from a pool of (length of Q powerset) possible states and AWWWRRGeerrghgh *must... resist... brain... thing.*



fruit.

6/13/2006 4:18:48 AM

timeconsumerx
129 Photos

the complex conjugate of sigma for set qsub0, abab is equal to the union of sigma of set p,b where p includes the complex conjugate of sigma for set qsub0, abab

equals the union of sigma of set p,b where p includes qsub0,1,3

equals sigma qsub0,b and the union of sigma qsub1,(3),b

implies that the given set equals qsub0, qsub2


this shit is so fucking gay. what a horrific proof.

6/13/2006 4:32:43 AM

Imperfect Clark
116 Photos

yapp.

note, p is a "production" where, a production is some mapping from some state q from set Q, to some other state in Q. That crazy symbol that p is an element of is the set of productions possible in the domain of the transition function defined for the acceptor.

The problem gets hairy because, this being a non-deterministic acceptor, means you can end up at different states for the same input symbol.. so at each step you have to analyze the possible scenarios that could've led up to that position, then determine all the possible scenarios that could happen from there. This algorithm is a way of turning the non-deterministic diagram (shown) into a deterministic one (where a one-to-one relationship exists between input and state transitions).

6/13/2006 5:02:14 AM

timeconsumerx
129 Photos

i'm taking deterministic OR this fall.

6/13/2006 8:01:08 AM

Lysander
1 Photos



[Edited by Lysander on 1/12/2007 10:26:08 AM. Reason for edit: .]

10/6/2006 10:35:30 AM

AntaresUSF
297 Photos

Fucking cocksucking educators. You don't teach kids with equations like this, jackasses; they'll never get it. Automata Theory isn't that difficult, but you give it to somebody in fucking Linear A and they're not gonna get it. Your professor needs to be bitch-slapped for this.

1/12/2007 12:35:23 PM

Imperfect Clark
116 Photos

Yeah.. the logic of the machine is simple, but theory purists love "disambiguating" algorithms with mathematics. The only point of knowing such formal definition is for proofs, which really are not the Computer Scientist's concern.

1/13/2007 12:07:05 AM

Lysander
1 Photos

cloggin up their brains imo

1/13/2007 2:27:33 AM




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